+++ title = "Decoding the FAST Protocol: Examples" date = 2022-01-11 draft = true [taxonomies] tags = ["finance", "binary", "protocol", "fix", "fast", "examples"] +++ After the whole explanation about the definition of the FAST protocol, I noticed there was something missing: Examples, to make things easier to understand. # Simple Hello World This example is basically the same one in [JetTek](https://jettekfix.com/education/fix-fast-tutorial/) but it is really simple, so here we go: ## Template ```xml ``` ## Incoming Data Bytes: ``` 1110_0000 1000_0001 0100_1000 0110_0101 0110_1100 0110_1100 0100_1111 0101_0111 0110_1111 0111_0010 0110_1100 1110_0100 ``` ## Processing The first byte is the Presence Map. Removing the stop bit, we get `110_0000`. This Presence Map have one field that isn't described in the template: The template ID. Because the first bit is set, we know the template ID is there. Also, keep in mind that the Template ID is the only field we know it exists so far; there is no information whatsoever about that second bit in the Presence Map -- we need to find out which template should be used first. The next byte is read: `1000_0001`. As mentioned above, this is the Template ID. Being a signed integer (and probably mandatory, but don't ask me how that works), we read the value, it has the stop bit, so that's the whole integer. Dropping the high order bit, we get the Integer "1", which is the exactly same ID we have in the template, so now we know which fields are here. The first field in the template is the string with a default value. Because the field uses the Default operator, we need to check if the value is in the data or we should use the default value. The bit in the Presence Map for this field is `1` meaning the value for the string is in the incoming data and we should read it. The field is string, so we keep reading every byte till we find one with the stop bit. Also, being a string, we don't "merge" the values: each byte is a letter in the ASCII table. The sequence is `100_1000` (72), `110_0101` (101), `110_1100` (108), `110_1100` (108), `100_1111` (79), `101_0111` (87), `110_1111` (79), `111_0010` (114), `110_1100` (108) and `110_0100` (100). Notice that we consumed all the bytes, and the last one have the stop, so that's the end of string. Converting the bytes using the ASCII string, we get "HelloWorld". So, there we have it: We received a record of the "HelloWorld" type, with the field ID "1" (a.k.a. "String") with the value "HelloWorld". # Sequences Let's expand our example to have a sequence and a few more operators: ## Template ```xml ``` Although FAST was defined to work with FIX and the financial market, there is nothing stopping it from being used for other things. The new template actually describe a group of users, so we have a list of groups and, for each group, a list of users and their IDs. ## Incoming Data ``` 1100_0000 1000_0010 1000_0011 0000_0011 0010_0011 0001_1000 1110_0111 1000_0010 1100_0000 0101_0101 0111_0011 0110_0101 0111_0010 1011_0001 1000_0100 1000_0000 0101_0101 0111_0011 0110_0101 0111_0010 1011_0010 ``` ## Processing As mentioned before, the first byte, `1100_0000` is the Presence Map of the root element with the leading Template ID. There is only one bit set, which means the Template ID is present. The second byte, `1000_0010` is the Template ID. Because it have the stop bit, that's the only byte for it. Removing the high order bit gives us `000_0010`, which is "2", so we know we are dealing with the "SequenceOfSequences" template. Now that we have the template and know the fields, we know what to read. The first field in our template is the sequence. The first thing we have in the sequence (and this is the first thing for *every* sequence) is the length of it. So we read the next byte, `1000_0011`, which is the only byte we need to read. It represents an unsigned int, which is "3", so this sequence have 3 elements -- and using our description in the previous sections, we know now that we have 3 groups. One point here: Because all fields in this sequence don't have any operators, it means the Presence Map doesn't exist. For sequences, every start of a new record contains a Presence Map only if at least one of the fields in the sequence require a Presence Map. That's not the case here. Because there is no Presence Map for the "OuterSequence", the next bytes are the "GroupID" field. We should read everything till we find the stop bit, so we get `0000_0011`, `0010_0011`, `0001_1000` and `1110_0111`. For every byte we remove the high order bit and then join everything into a single thing, in this case `000_0011 010_0011 001_1000 110_0111` or simply `0000_0110_1000_1100_1100_0110_0111`; this value, being an unsigned int, is "6868070". Here is a good point to remind that, because the field is mandatory, it means that's actually the value of "GroupID"; if the field as optional, the actual value would be "6868069". Now for he "InnerSequence" field. The first step is to gather the number of elements (the length of the sequence). That's the `1000_0010` byte, which is "2". So there are two users in this group. Because "InnerSequence" has a field that uses the Presence Map ("ID" uses the Increment operator, so we need to check if there is an incoming value for it or we should just increment the value), the first thing after the length is the Presence Map for this record. The byte `1100_0000` indicates that the first field that requires a Presence Map is present. But that's not the time to use the Presence Map yet. The field after the length is the "Username", which is a mandatory string. Mandatory strings with no operators are always present and we don't need to check the map. Same as we did with "String" in the example for Hello World, we read the bytes till the stop bit, but don't merge them: `0101_0101` (85), `0111_0011` (115), `0110_0101` (101), `0111_0010` (114) and `1011_0001` (49, if we remove the stop bit, that is), which converted by the ASCII table gives us "User1". Remember that we jumped the Presence Map? Now it is the time to use it, since we are reading "ID" and it has an operator that requires the Presence Map. The Presence Map we read before was `100_0000` (with the stop bit removed), so yeah, the "ID" is present. We read the next byte, `1000_0100`, which is "4". But there is a gotcha here: The field is optional. So although we read "4", the actual value is "3" -- if the value read was "0" it meant that the ID is Null. Good. We just finished reading the first record of "InnerSequence". Now we read the second record. We don't need to read the length again, but we need to read the Presence Map for this record. It is the byte `1000_0000`, a Presence Map indicating that none of the fields with operators are present. But, again, it is not the time for the Presence Map, but for the "Username". The bytes for the field are `0101_0101` (85), `0111_0011` (115), `0110_0101` (101), `0111_0010` (114) and `1011_0001` (50), which is "User2".